Derivative of $l o g | x |$ w.r.t. $| x |$ is

$\frac{1}{x}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{1}{| x |}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\pm \frac{1}{x}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$\frac{1}{| x |}$

Let $| x | = t$ , then we are required to find $\frac{d}{d t} (l o g t) = \frac{1}{t} = \frac{1}{| x |}$

Suggest Corrections

Similar questions

The derivative of log [log(logx)]w.r.t x is:

Derivative of $l o g | x |$ w.r.t. $| x |$ is

log sin x

\sqrt{cos x}

(x^{2} + 1) log x - e^{x} cos x w . r . t x

(log x)^{x}

x

(log x)^{x - 1} [1 + log x log (log x)]

\frac{d}{d x} {f (x)^{g (x)}} = f (x)^{g (x)}

(g (x) \frac{f^{'} (x)}{f (x)} + g^{'} (x) log (f (x)))

Join BYJU'S Learning Program