Question

$\frac{2x}{3}-\frac{x-1}{6}+\frac{7x-1}{4}=2\frac{1}{6}$

Answer 1

$\Rightarrow \frac{2x}{3}-\frac{(x-1)}{6}+\frac{7x-1}{4}=2\frac{1}{6}$

$\Rightarrow \frac{24x-6x+6+63x-9}{36}=\frac{13}{6}$

$\Rightarrow 81x-3=78$

$\Rightarrow 81x=78+3=81$

$\Rightarrow x=1$