Consider given equations
2x−3y=15 ………….(1)
8x+5y=77 ………….(2)
Let,u=1x,v=1y then, we get
2u-3v=15 ……………..(3)
8u+5v=77 ………………(4)
From equation (3) u=15+3v2 put in equation (4), we get
8×(15+3v2)+5v=77
4(15+3v)+5v=77
60+12v=77
v=1712
Put the value of v in equation (3).
2u−3×1712=15
2u=15+174=774
u=778
Now,
1x=u,1y=v
1x=778,1y=7712
x=877,y=1277
Hence, this is the answer,