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Question

Differentiate given problems w.r.t.x.

(3x29x+5)9.

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Solution

Let y = (3x29x+5)9

Differentiating w.r.t. x, we get

dydx=9(3x29x+5)8ddx=9(3x29x+5)

=9(3x29x+5)8(6x9)=9×3(2x3)(3x29x+5)8

=27(2x3)(3x29x+5)8


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