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Question

π/6π/3dx1+tanx

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Solution

I=π6π3dx1+tanx......(i)I=π6π3dx1+tan(π2x)I=π6π3dx1+cotxI=π6π3tanxdxtanx+1.......(ii)

Adding (i) and (ii)

2I=π6π32I=π6I=π12


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