Question

Draw an angle measuring ${75}^{\circ }$ and bisect it.

Answer 1

We have ${60}^{\circ }+{15}^{\circ }={75}^{\circ }$ and $\frac{1}{2}{75}^{\circ }={37.5}^{\circ }$

$1.$Draw a straight line $AB=6$cms

$2.$ From $A$ draw an arc of length $AB=6$cms.

$3.$From $B$ with the same length of $AB=6$cms.Name it as $C$

$4.$From $C$ with the same length of length $AB=6$cms.Name it as $D$

$5.$Bisect the arc $CD$.Join $AE$

$6.$Bisect $CE$.Join $FA$

$\therefore ,\angle BAF={75}^{\circ }$

$7.$Bisect $\angle BAF={75}^{\circ }$

$\therefore \angle BAG=37.5$degrees