Question

Each rectangular tile is $40cm$ long and $30cm$ wide. How many tiles will be required to cover the floor of a room with length $=4.8m$ and breadth $=2.4m.$

Answer 1

Given,
Length of the rectangular tile $=40cm$ and
Breadth of the rectangular tile $=30cm$
$\because 100cm=1m$
Thus,
$40cm=\frac{1}{100}\times 40=0.4m$
$30cm=\frac{1}{100}\times 30=0.3m$
The area of the rectangular tile is given by:
$=\text{length}\times \text{breath}$
$=0.4\times 0.3=0.12m^2$

Given,
Rectangular floor of the room,
Length $=4.8m$&
Breadth $=2.4m$
The area of the rectangular floor of the room is given by.
$=\text{length}\times \text{breath}$
$=4.8\times 2.4=11.52m^2$

Number of tiles
$=\frac{\text{Area of the floor}}{\text{Area of each tile}}$
$=\frac{11.52}{0.12}\times \frac{100}{100}$
$=\frac{1152}{12}=96$

Therefore, the number of tiles required would be $96$.