Evaluate -1-2-5 - Maths Q-A

Given (1/2)^ 5To find the valueConsider (1/2)^ 5 =(1/2)^ 50ex0ex=1/(1/2)^50ex0ex=1/1^5/2^50ex0ex=1/1/250ex0ex= 1× 25/1× 10ex0ex=25/10ex0ex=25Hence ...

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Standard XII

Mathematics

Substitution Method to Remove Indeterminate Form

Evaluate (1/2...

Question

Evaluate ${(\frac{1}{2})}^{- 5}$

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Solution

Given ${(\frac{1}{2})}^{- 5}$
To find the value
Consider ${(\frac{1}{2})}^{- 5}$
$= {(\frac{1}{2})}^{- 5} = \frac{1}{{(\frac{1}{2})}^{5}} = \frac{1}{\frac{1^{5}}{2^{5}}} = \frac{1}{\frac{1}{25}} = \frac{1 \times 25}{1 \times 1} = \frac{25}{1} = 25$
Hence, ${(\frac{1}{2})}^{- 5}$ is $25$

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Evaluate 12-5

Given 12-5To find the valueConsider 12-5 =12-5=1125=11525=1125=1×251×1=251=25Hence, 12-5 is 25

Evaluate ${(\frac{1}{2})}^{- 5}$

Given ${(\frac{1}{2})}^{- 5}$
To find the value
Consider ${(\frac{1}{2})}^{- 5}$
$= {(\frac{1}{2})}^{- 5} = \frac{1}{{(\frac{1}{2})}^{5}} = \frac{1}{\frac{1^{5}}{2^{5}}} = \frac{1}{\frac{1}{25}} = \frac{1 \times 25}{1 \times 1} = \frac{25}{1} = 25$
Hence, ${(\frac{1}{2})}^{- 5}$ is $25$