We can compute this by multiplying both numerator and denominator by the conjugate, 1+i, of the denominator.
(1+i1−i)⋅(1+i1+i)=1+2i+i21−i2
We know that i2=−1, so:
1+2i+i21−i2=1+2i−11−(−1)=2i2=i.