Evaluate -101-210-201-10-401-10-211-10-209-

The correct option is A 10,201 Using the identity nbsp;(a + b)^2= nbsp;a^2 +2ab + b^2, we have (101)^2 nbsp;=(100+1)^2 nbsp; nbsp; nbsp; nbsp; ...

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Byju's Answer

Standard VII

Mathematics

(a + b)^2 = a^2 + 2ab +b^2

Evaluate :101...

Question

Evaluate : $101^{2}$

10,209

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10,201

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10,401

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10,211

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Solution

The correct option is B
10,201

Using the identity $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ , we have
$(101)^{2}$ $= (100 + 1)^{2}$
$= (100)^{2} + 2 (100) (1) + (1)^{2}$
$= 10000 + 200 + 1$
$= 10, 201$

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Evaluate :1012

The correct option is B 10,201 Using the identity (a+b)2=a2+2ab+b2, we have (101)2 =(100+1)2 =(100)2+2(100)(1)+(1)2 =10000+200+1 =10,201

Evaluate : $101^{2}$

The correct option is B
10,201

Using the identity $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ , we have
$(101)^{2}$ $= (100 + 1)^{2}$
$= (100)^{2} + 2 (100) (1) + (1)^{2}$
$= 10000 + 200 + 1$
$= 10, 201$