Evaluate : 1012
10209
10201
10401
10211
The correct option is C: 10201
(101)2=(100+1)2
=(100)2+2×100×1+12
[Using the identity (a+b)2=(a2+2ab+b2)]
=10000+200+1
=10201
Evaluate :
(i) 372−362 (ii) 852−842
(iii) 1012−1002