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Question

Evaluate : 1012


A

10209

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B

10201

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C

10401

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D

10211

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Solution

The correct option is C: 10201

(101)2=(100+1)2

=(100)2+2×100×1+12

[Using the identity (a+b)2=(a2+2ab+b2)]

=10000+200+1

=10201


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