((999)^2 1) =(999)^2 (1)^2 We know the formula a^2 b^2=(a+b)(a b) (999+1)(999 1) =1000 × 998 =998000 ...

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Algebraic Identities

Evaluate 9992...

Question

Evaluate $((999)^{2} - 1)$ .

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Solution

$((999)^{2} - 1) = (999)^{2} - (1)^{2}$

We know the formula

$a^{2} - b^{2} = (a + b) (a - b) (999 + 1) (999 - 1) = 1000 \times 998 = 998000$

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