Evaluate:
(i) (8)³
(ii) (15)³
(iii) (21)³
(iv) (60)³

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Solution

(i) (8)³ = $(8 \times 8 \times 8)$ = 512.
Thus, the cube of 8 is 512.
(ii) (15)³= $(15 \times 15 \times 15)$ = 3375.
Thus, the cube of 15 is 3375.
(iii) (21)³= $(21 \times 21 \times 21)$ = 9261.
Thus, the cube of 21 is 9261.
(iv) (60)³= $(60 \times 60 \times 60)$ = 216000.
Thus, the cube of 60 is 216000.

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Similar questions

Evaluate :
(i) $(8)^{3}$ (ii) $(15)^{3}$ (iii) $(21)^{3}$ (iv) $(60)^{3}$

Q. Add.
(i)

6 \frac{1}{3} + 2 \frac{1}{3}

(ii)

1 \frac{1}{4} + 3 \frac{1}{2}

(iii)

5 \frac{1}{5} + 2 \frac{1}{7}

(iv)

3 \frac{1}{5} + 2 \frac{1}{3}

Q. Evaluate the determinants (i) (iii) (ii) (iv)

Evaluate :
(i) $(1.2)^{3}$ (ii) $(3.5)^{3}$ (iii) $(0.8)^{3}$ (iv) $(0.05)^{3}$

Simplify
(i) $2^{\frac{2}{3}} \times 2^{\frac{1}{3}}$
(ii) $2^{\frac{2}{3}} \times 2^{\frac{1}{5}}$
(iii) $7^{\frac{5}{6}} \times 7^{\frac{2}{3}}$
(iv) $(1296)^{\frac{1}{4}} \times (1296)^{\frac{1}{2}}$

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Evaluate: (i) (8)3 (ii) (15)3 (iii) (21)3 (iv) (60)3

(i) (8)3 = 8×8×8= 512.Thus, the cube of 8 is 512.(ii) (15)3 = 15×15×15= 3375.Thus, the cube of 15 is 3375.(iii) (21)3 = 21×21×21= 9261.Thus, the cube of 21 is 9261.(iv) (60)3 = 60×60×60= 216000.Thus, the cube of 60 is 216000.

Evaluate:
(i) (8)³
(ii) (15)³
(iii) (21)³
(iv) (60)³