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Question

Evaluate dxx(x3+8).

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Solution

Let I=dxx(x3+8)=133x2dxx3(x3+8)

Put x3+8=t3x3dx=dt

I=13dt(t8)t1318×(1t81t)

124[log|t8|log|t|]+C

I=124logx3x3+8+C


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