Evaluate.
(i) 9 × (− 3) × (− 6)
(ii) (− 5) × (− 10) × (− 7) × 2
(iii) (− 18) × (− 43) × 0
(iv) (− 9) × (− 8) × (− 1) × 1
(v) − 12 × (− 15) × 6 × 4
(vi) − 7 × (− 4) × (− 6) × (− 2)

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Solution

(i) Taking the absolute value of all the numbers
9 $\times$ 3 $\times$ 6 = 162
Now the number of negative integers is two which is even
Therefore the correct answer is 162

(ii) Taking the absolute value of all the numbers
5 $\times$ 10 $\times$ 7 $\times$ 2=700
Now the number of negative integers is 3 which is odd
Therefore the correct answer is −700

(iii)Taking the absolute value of all the numbers
18 $\times$ 43 $\times$ 0 = 0
Since zero is neutral hence we do not need to put any sign

(iv) Taking the absolute value of all the numbers
9 $\times$ 8 $\times$ 1 $\times$ 1=72
Now the number of negative integers is 3 which is odd
Therefore the correct answer is −72

(v) Taking the absolute value of all the numbers
12 $\times$ 15 $\times$ 6 $\times$ 4=43209
Now the number of negative integers is 2 which is even
Therefore the correct answer is 4320

(vi) Taking the absolute value of all the numbers
7 $\times$ 4 $\times$ 6 $\times$ 2=336
Now the number of negative integers is 4 which is even
Hence the correct answer is 336

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Similar questions

Evaluate : $(i) \frac{5}{9} + \frac{- 7}{6} (i i) 4 + \frac{3}{- 5} (i i i) \frac{1}{- 15} + \frac{5}{- 12} (i v) \frac{5}{9} + \frac{3}{- 4} (v) \frac{- 8}{9} + \frac{- 5}{12} (v i) 0 + \frac{- 2}{7} (v i i) \frac{5}{- 11} + 0 (v i i i) 2 + \frac{- 3}{5} (i x) \frac{4}{- 9} + 1$

source $(i) \frac{8}{9} + \frac{- 11}{6} (i i) 3 + \frac{5}{- 7} (i i i) \frac{1}{- 12} a n d \frac{2}{- 15} (i v) \frac{- 8}{19} + \frac{- 4}{57} (v) \frac{7}{9} + \frac{3}{- 4} (v i) \frac{5}{26} + \frac{11}{- 39} (v i i) \frac{- 16}{9} + \frac{- 5}{12} (v i i i) \frac{- 13}{8} + \frac{5}{36} (i x) 0 + \frac{- 3}{5} (x) 1 + \frac{- 4}{5} (x i) \frac{- 5}{16} + \frac{7}{24}$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Subtract :

(i) $\frac{3}{4}$ from $\frac{1}{3}$ (ii) $\frac{- 5}{6}$ from $\frac{1}{3}$ (iii) $\frac{- 8}{9}$ from $\frac{- 3}{5}$

(iv) $\frac{- 9}{7}$ from -1 (v) $\frac{- 18}{11}$ from 1 (vi) $\frac{- 13}{9}$ from 0

(vii) $\frac{- 32}{13}$ from $\frac{- 6}{5}$ (viii) -7 from $\frac{- 4}{7}$

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

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Evaluate. (i) 9 × (− 3) × (− 6) (ii) (− 5) × (− 10) × (− 7) × 2 (iii) (− 18) × (− 43) × 0 (iv) (− 9) × (− 8) × (− 1) × 1 (v) − 12 × (− 15) × 6 × 4 (vi) − 7 × (− 4) × (− 6) × (− 2)

Evaluate.
(i) 9 × (− 3) × (− 6)
(ii) (− 5) × (− 10) × (− 7) × 2
(iii) (− 18) × (− 43) × 0
(iv) (− 9) × (− 8) × (− 1) × 1
(v) − 12 × (− 15) × 6 × 4
(vi) − 7 × (− 4) × (− 6) × (− 2)