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Question

Evaluate: 35|x+2|dx

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Solution

Solution :- given
53|x+2|dx
for 5x2:(x2)
2x3:(x+2)
Integration can be written as
=52(x2)dx+23(x+2)dx
=25[x222x]+ 32[x22+2x]
=[((2)2+2×2)((5)22)+2×5]+[(322+2.3)((2)22+2.(2))]
=[(42+4)(252+10)]+[(92+6)(424)]
=[(2+4)(25+202)]+[(9+122)(24)]
=[2+52]+[212+2]
=92+252
=342
=17 Ans

1149171_1228408_ans_8ea909a88fc345f3be7b21d98972c3ad.jpg

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