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Question

Evaluate
dx(x2+1)x2+1

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Solution

We have,

dx(x2+1)x2+1

So,

dx(x2+1)2(x2+1)

dx(x2+1)32

(x2+1)32dx

On integrating and we get,

(x2+1)3232+C

2(x2+1)323+C

Hence, this is the answer.


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