Evaluate-m2 - 11m - 42 - m - 32 Marks

Let us first factorise m^2 nbsp; 11m 42: = m^2 14m+3m 42 = m(m 14)+3(m 14) = (m+3)(m 14) ...(1 Mark) Let us now divide: (m+3)(m 14)/(m+3)=(m 14) ...(1 Ma ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation

Evaluate:m2 -...

Question

Evaluate:

$(m^{2} - 11 m - 42) \div (m + 3)$

(2 Marks)

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Solution

Let us first factorise $m^{2} - 11 m - 42$ :
$= m^{2} - 14 m + 3 m - 42$
$= m (m - 14) + 3 (m - 14)$
$= (m + 3) (m - 14)$
...(1 Mark)

Let us now divide:
$\frac{(m + 3) (m - 14)}{(m + 3)} = (m - 14)$
...(1 Mark)

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Factorise and divide the expressions given

i.) $(m^{2} - 11 m - 42) \div (m + 3)$

ii.) $39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)$ [4 MARKS]

Q. Find the value of m in the equation 11m - 8 - m = 9 + m
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Q. 32 + 42 + 65 + 82 = 82 + + 42 + 32

Q.
Jimmy found the mode of the given data as 32. Is he correct or not? Justify.
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how to solve these sums?

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Evaluate: (m2−11m−42)÷(m+3) (2 Marks)

Let us first factorise m2−11m−42: =m2−14m+3m−42 =m(m−14)+3(m−14) =(m+3)(m−14) ...(1 Mark) Let us now divide: (m+3)(m−14)(m+3)=(m−14) ...(1 Mark)

Evaluate:

$(m^{2} - 11 m - 42) \div (m + 3)$

(2 Marks)

Let us first factorise $m^{2} - 11 m - 42$ :
$= m^{2} - 14 m + 3 m - 42$
$= m (m - 14) + 3 (m - 14)$
$= (m + 3) (m - 14)$
...(1 Mark)

Let us now divide:
$\frac{(m + 3) (m - 14)}{(m + 3)} = (m - 14)$
...(1 Mark)