Consider the given expression.
⇒sin2900cos2450+4tan230+12sin2a−2cos2900+124
Put the value of all trigonometry function in given expression, we get
⇒sin2900cos2450+4tan230+12sin2a−2cos2900+124
⇒(1)2.(1√2)2+4.(1√3)2+12sin2a−2(0)2+124
⇒12+43+12sin2a+124
⇒12sin2a+12+32+1224
⇒12sin2a+5624
⇒12sin2a+73
Hence, this is the answer.