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Question

Evaluate the limit:

limx02xsinxtanx+x

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Solution

We have,

limx02xsinxtanx+x

It becomes 0/0 form.

=limx0x(2sinxx)x(tanxx+1)

=limx0(2sinxx)(tanxx+1)

[limx0sinxx=1,limx0tanxx=1]

=211+1

=12

Therefore,

limx02xsinxtanx+x=12

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