The correct option is
D x2−16The product
(x+4)(x−4) can be evaluated using Foil method as:
Step 1:––––––––
We would multiply the "FIRST" terms of both the brackets given in the product
(x+4)(x−4) i.e.
x and
x.
x×x=x2
The first term of the product
(x+4)(x−4) is
x2.
Step 2:––––––––
Now, we would multiply the "OUTER" terms of the product
(x+4)(x−4) i.e.
x and
−4
x×(−4)=−4x
The second term of the product
(x+4)(x−4) is
−4x.
Step 3:––––––––
Now, we would multiply the "INNER" terms of the product
(x+4)(x−4). (i.e.,
4 and
x)
4×x=4x
The third term of the product
(x+4)(x−4) is
4x.
Step 4:––––––––
Now, we would multiply the "LAST" terms of the product
(x+4)(x−4). (i.e.,
4 and
−4)
4×(−4)=−16
The fourth term of the product
(x+4)(x−4) is
−16.
Step 5:––––––––
To find the value of the product
(x+4)(x−4), we need to add all the terms.
Product
= First term
+ Second term
+ Third term
+ Fourth term
Hence,
(x+4)(x−4) is
=x2+(−4x)+4x+(−16)
=x2−4x+4x–––––––––––−16
=x2−16
The value of the product
(x+4)(x−4) is
x2−16.
Therefore, option (d.) is the correct answer.