Evaluate (x3+2x2+3x)÷2x
The correct option is A (x2+2x+3)2 We have
(x3+2x2+3x)÷2x
=[(x×x×x)+(2×x×x)+(3×x)]÷2x
=x(x2+2x+3)2x
=(x2+2x+3)2
limx→∞{x2+2x+32x2+x+5}3x−23x+2