Expand $(3 x - 2 y + 4) (3 x - 2 y - 4)$

9 x^{2} - 12 x y + 4 y^{2} - 16

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9 x^{2} + 12 x y + 4 y^{2} + 16

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27 x^{2} - 12 x y + 4 y^{2} - 9

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27 x^{2} - 12 x y + 4 y^{2} - 16

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Solution

The correct option is A $9 x^{2} - 12 x y + 4 y^{2} - 16$
Given: $[(3 x - 2 y) + 4] [(3 x - 2 y) - 4]$

Taking $3 x - 2 y = a$

= $(a + 4) (a - 4)$

= $a^{2} - 16$ .......[ $(a + 4) (a - 4) = a^{2} - 4^{2}$ ]

= $(3 x - 2 y)^{2} - 16$

= $(3 x)^{2} - (2 \times 3 x \times 2 y) + (2 y)^{2} - 16$

= $9 x^{2} - 12 x y + 4 y^{2} - 16$

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(x - 3) (x - 1) + (y - 2) (y - 4)

{(3 x + 2 y)}^{4}

(3 x + 2 y - z)^{2}

Solve and find x and y:-

1/2(x+2y) +5/4(3x-2y)=-3/2 -------(i)

5/4(x+2y) - 3/5(3x-2y)=61/60 ---------(ii)

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