Consider
loga3√x7y8÷4√z
loga3√x7y8÷4√z=loga(3√x7y84√z)
=loga(x7y84√z)13
=13loga(x7y84√z)
=13{loga(x7y8)−loga(4√z)}
=13⎧⎪⎨⎪⎩loga(x7y8)−loga(z)14⎫⎪⎬⎪⎭
=13{loga(x7y8)−14loga(z)}
=13{loga(x7)+loga(y8)−14loga(z)}
loga3√x7y8÷4√z=13{7loga(x)+8loga(y)−14loga(z)}