Given: Expression is (2x–5)(2x+5)(2x–3).
First expand the given binomials(2x–5)(2x+5)by the difference of square identity.
⇒(2x–5)(2x+5)=(2x)2−(5)2
[∵(a+b)(a−b)=a2−b2]
=4x2−25
Now, multiply the result (4x2−25) by (2x−3)
⇒(4x2−25)(2x−3)=4x2×(2x−3)−25×(2x−3)
=8x3−12x2−50x+75
Hence, (2x–5)(2x+5)(2x–3)=8x3−12x2−50x+75.