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Question

Expand using suitable identities
(2a3b)3

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Solution

We need to expand (2a3b)3
We know suitable identity is (xy)3=x33x2y+3xy2+y3
Here x=2a and y=3b
Therefore, value of (2a3b)3 is
=(2a)33(2a)2(3b)+3(2a)(3b)2(3b)3
=8a336a2b+54ab227b3

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