Question

Explain the shape of $Br{F}_5$.

Answer 1

In $Br{F}_5$ molecule:

Number of bond pairs $=5$

Number of lone pairs on central atom $=1$

So, $Br{F}_5$ molecule is surrounded by six electron pairs. Hybridisation of $Br$ atom in this molecule is $s{p}^3{d}^2$. Five positions are occupide by $F$ atoms forming sigma bonds with $s{p}^3{d}^2$ hybrid orbitals and one position occupied by lone pari. So, the molecule has a square pyramidal shape.