Solve
3x2:3x = 9:1.
(2, -2)
(1, -1)
(1, -2)
Given
3x2:3x = 9:1
⇒ 3x23x = 91
⇒ 3x2 = 9×3x
⇒ 3x2 = 32×3x
⇒ 3x2 = 32+x
Equating the powers
x2=2+x
x2−x−2=0
Solving this we get
x=2,−1
The oxidation numbers of C - 1 and C - 2 in propene CH32CH=1CH2 are respectively
3x3+2x2+3x+2=?
(a) (3x−2)(x2−1)
(b) (3x−2)(x2+1)
(c) (3x+2)(x2−1)
(d) (3x+2)(x2+1)
If f(x)=cos2x+sec2x, then