Question 67 (f)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

$m^{2} n^{2} + n^{2} p^{2} + p^{2} m^{2}$

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Solution

Given, m = 1, n = -1 and p = 2
So, putting m = 1, n = -1 and p = 2 in the given expression, we get
$m^{2} n^{2} + n^{2} p^{2} + p^{2} m^{2} = (1)^{2} (- 1)^{2} + (- 1)^{2} (2)^{2} + (2)^{2} (1)^{2} = 1 + 4 + 4 = 9$

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Similar questions

m^{2} n^{2} + n^{2} p^{2} + p^{2} m^{2}

Question 67 (a)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

m + n + p

Question 67 (d)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

mn + np + pm

Question 67 (c)

Find the value of the given polynomial at m = 1, n = -1 and p = 2

$m^{3} + n^{3} + p^{3}$

Question 66 (f)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a^{2} - b^{2}}{3}$

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