f(x)= x+1 and g(x)= x2 -2. Find(gof)-1([-2,-1])
Option (d)
gof (x) = g(f(x))= g(x+1) = (x+1)2-2= x2 +2x -1
-2 ≤x2 +2x -1≤-1
-1≤x2 +2x≤0
x(x+2) ≤0
- 2 ≤ x ≤ 0
[-2,0]