Consider the given function
f(x)=x2+x
D=R
sothatD(−∞,∞),R(0.∞)
putthany=x2
∴D(−∞,∞),R(−∞,−1)
Hence this is the answer.
f(x)=x2 for x < 2
g(x)= x2 for x > -1
Range of f(x)= range of g(x)
The range of f(x) = x2+x+1x2+x−1