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Question

Factories:
x3+13x2+32x+20

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Solution

x313x2+32x+20

=x3+13x2+30x+2x+20

=x(x2+13x+30)+2x+20 [Taking x as common]

=x(x2+10x+3x––––––––+30)+2(x+10)

=x{x(x+10)+3(x+10)}+2(x+10)

=x(x+3)(x+10)+2(x+10)

=(x+10){x(x+3)+2}

=(x+10)(x2+3x+2)

=(x+10)(x2+2x+x+2)

=(x+10){x(x+2)+1(x+2)}

=(x+10){(x+1)(x+2)}

=(x+10)(x+1)(x+2)



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