Factorise-1 2 y2-11 y-52 x2-2 x-803 3 x2-4 x-1

(1) 2y2 minus; 11y nbsp;+ 5 =2y2 10y y+5=2yy 5 1y 5=y 52y 1 (2) nbsp;x2 nbsp; minus; 2x nbsp; minus; 80 =x2 10x+8x 80=xx 10+8x 10=x 10x+8 (3) ...

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Byju's Answer

Standard IX

Mathematics

By Grouping

Factorise.1 2...

Question

Factorise.
(1) 2y²−11y+5
(2) x²−2x−80
(3) 3x²−4x+1

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Solution

(1) 2y² − 11y + 5

$= 2 y^{2} - 10 y - y + 5 = 2 y (y - 5) - 1 (y - 5) = (y - 5) (2 y - 1)$

(2) x²− 2x − 80

$= x^{2} - 10 x + 8 x - 80 = x (x - 10) + 8 (x - 10) = (x - 10) (x + 8)$

(3) 3x²− 4x + 1

$= 3 x^{2} - 3 x - x + 1 = 3 x (x - 1) - 1 (x - 1) = (x - 1) (3 x - 1)$

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