1029 3x3 = 3(343 x3) = 3(73 x3) = 3(7 x)(72 + 7x + x2) = 3(7 x)(49 + 7x + x2) ...

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Factorisation Using Algebraic Identities

Factorise: 10...

Question

Factorise:

$1029 - 3 x^{3}$

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Solution

1029 - 3x³

= 3(343 - x³)

= 3(7³ - x³)

= 3(7 - x)(7² + 7x + x²)

= 3(7 - x)(49 + 7x + x²)

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