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Question

Factorise:
(2a+1)3+(a1)3

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Solution

(2a+1)3+(a1)3=(2a+1+a1)((2a+1)2+(a1)2(2a+1)(a1))=(3a)(4a2+1+4a+a2+12a2a2+2aa+1)=(3a)(3a2+3a+3)=(9a)(a2+a+1)


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