Factorise $2 x^{2} + 11 x + 15$

$(x - 5) (2 x - 3)$

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$(x + 3) (2 x + 5)$

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$(x + 5) (2 x - 3)$

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$(x - 5) (2 x + 3)$

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Solution

The correct option is B
$(x + 3) (2 x + 5)$

$2 x^{2} + 11 x + 15$
= $2 x^{2} + 6 x + 5 x + 15$
(Since 15 x 2= 30, it can be split as (6 )+(5) = 11 and 6 x 5=30 )
= ( $2 x (x + 3) + 5 (x + 3)$
= $(x + 3) (2 x + 5)$

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