Given: 2x2−24x+72 =2(x2−12x+36), (take 2 common)
=2(x2−6x−6x+36), (split middle term)
=2[(x2−6x)+(−6x+36)],( group pair of terms)
=2[x(x−6)−6(x−6)], (factor each binomials)
=2(x−6)(x−6)
=2(x−6)2
Aliter, use (a−b)2=a2−2ab+b2
⇒2(x2−12x+36)=2(x2−2×6x+62)=2(x−6)2