Factorise $2 x^{2} - 7 x + 6$

(x-2)(2x-1)

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(x-1)(2x-3)

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(x-2)(2x-3)

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(2x-2)(2x-3)

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Solution

The correct option is C
(x-2)(2x-3)

$2 x^{2} - 7 x + 6 = 2 x^{2} - 4 x - 3 x + 6$

$= 2 x (x - 2) - 3 (x - 2)$

$= (x - 2) (2 x - 3)$

Hence the factored form of $2 x^{2} - 7 x + 6$ is $(x - 2) (2 x - 3)$

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