Question

Factorise: $2x^2-\frac{5}{6}x+\frac{1}{12}$

Answer 1

Given $2x^2-\frac{5}{6}x+\frac{1}{12}$
$\Rightarrow 2x^2-\frac{1}{2}x-\frac{1}{3}x+\frac{1}{12}$
$\Rightarrow x(2x-\frac{1}{2})-\frac{1}{6}(2x-\frac{1}{2})$
$\left\{\begin{array}{c}\because 2\times \frac{1}{12}=\frac{2}{12}=\frac{1}{6}\\ \because \frac{1}{6}=\frac{-1}{2}\times \frac{-1}{3}\\ \frac{-5}{6}=\frac{-1}{2}-\frac{1}{3}\end{array}\right\}$
$\Rightarrow (2x-\frac{1}{2})(x-\frac{1}{6})$