Factorise :

$(3 x - 2 y)^{2} + 3 (3 x - 2 y) - 10$

Open in App

Solution

$(3 x - 2 y)^{2} + 3 (3 x - 2 y) - 10 = (3 x - 2 y)^{2} + 5 (3 x - 2 y) - 2 (3 x - 2 y) - 10 = (3 x - 2 y) (3 x - 2 y + 5) - 2 (3 x - 2 y + 5) = (3 x - 2 y + 5) (3 x - 2 y - 2)$

Suggest Corrections

Similar questions

(3 x - 2 y)^{2} + 3 (3 x - 2 y) - 10

{(3 x - 2 y)}^{2} + 3 (3 x - 2 y) - 10

{(x - 2 y)}^{2} + 7 (x - 2 y) + 12

{(4 x + y)}^{2} + (4 x + y) (x + 2 y) - 20 {(x + 2 y)}^{2}

9 (x - 2 y)^{2} - 4 (x - 2 y) - 13

Join BYJU'S Learning Program