Question

Factorise:

√3x²+11x+6√3

Answer 1

Let a and b be the roots
then if we factorise it
it will be in the form (x-a)(x-b)
a+b=-11/root(3)
ab=6root(3)/root(3)
ab=6
so by equationg this 2 equations
we will get
a=-9/root(3)
b=-2/root(3)
so
root(3)x^2+11x+6root(3)
={x+[9/root(3)]}{x+[2/root(3)]}

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