Factorise- 4p-2 - 9q-2 - Maths Q-A

Factorise the polynomial4p^2 9q^20ex0ex=(2p)^2 (3q)^2using the identity𝑎^2 𝑏^2=(𝑎+𝑏)(𝑎 𝑏)=(2p+3q)(2p 3q)Hence, the factors of the polynomial 4p^2 9q^2are (2p+3 ...

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Standard VIII

Mathematics

Division of a Monomial by Another Monomial

Factorise: 4p...

Question

Factorise: $4 p^{2} - 9 q^{2}$ .

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Solution

Factorise the polynomial
$4 p^{2} - 9 q^{2} = {(2 p)}^{2} - {(3 q)}^{2}$
using the identity $a^{2} - b^{2} = (a + b) (a - b)$
$= (2 p + 3 q) (2 p - 3 q)$
Hence, the factors of the polynomial $4 p^{2} - 9 q^{2}$ are $(2 p + 3 q)$ and $(2 p - 3 q)$ .

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Factorise: 4p2-9q2.

Factorise the polynomial4p2-9q2=(2p)2-(3q)2using the identitya2-b2=(a+b)(a-b)=(2p+3q)(2p-3q)Hence, the factors of the polynomial 4p2-9q2are (2p+3q)and (2p-3q).

Factorise: $4 p^{2} - 9 q^{2}$ .

Factorise the polynomial
$4 p^{2} - 9 q^{2} = {(2 p)}^{2} - {(3 q)}^{2}$
using the identity $a^{2} - b^{2} = (a + b) (a - b)$
$= (2 p + 3 q) (2 p - 3 q)$
Hence, the factors of the polynomial $4 p^{2} - 9 q^{2}$ are $(2 p + 3 q)$ and $(2 p - 3 q)$ .