Factorise: 6√3x2−47x+5√3
Given
6√3x2−47x+5√3⇒6√3x2−45x−2x+5√3⇒3√3x(2x−5√3x)−1(2x−5√3)⇒(3√3x−1)(2x−5√3x)
Hence (6√3x2−47x+5√3 is (3√3x−1)(2x−5√3x))
Factorise:
√3x2+11x+6√3
2√3x2+x−5√3