Factorise:

$64 - a^{3} b^{3}$

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Solution

$W e k n o w a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2}) 64 - a^{3} b^{3} = 4^{3} - (a b)^{3} = (4 - a b) (4^{2} + 4 a b + (a b)^{2}) = (4 - a b) (16 + 4 a b + a^{2} b^{2})$

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