Question

Factorise:

$64-a^3{b}^3$

Answer 1

$Weknow{a}^3-b^3=(a-b)(a^2+ab+b^2)64-a^3{b}^3=4^3-(ab{)}^3=(4-ab\left)\right(4^2+4ab+\left(ab{)}^2\right)=(4-ab)(16+4ab+a^2{b}^2)$