Factorise: $9 x^{3} - 6 x^{2} + 12 x$

3 x (3 x^{2} - 2 x + 4)

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x (3 x^{2} - 2 x + 4)

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x (3 x^{2} - 2 x - 4)

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3 x (3 x^{2} - x + 7)

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Solution

The correct option is A $3 x (3 x^{2} - 2 x + 4)$
factorising $9 x^{3} - 6 x^{2} + 12 x$
Take $3 x$ as common,
$= 3 x (3 x^{2} - 2 x + 4)$

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Similar questions

1) $\int \frac{x^{3} + 3 x + 4}{\sqrt{x}} d x$

2) $\int \sqrt{x} (3 x^{2} + 2 x + 3) d x$

3) $\int (2 x^{2} - 3 sin x + 5 \sqrt{x}) d x$

4) $\int \frac{{sec}^{2} x}{{csc}^{2} x} d x$

\int \sqrt{x} (3 x^{2} + 2 x + 3) d x

\int \sqrt{x} (3 x^{2} + 2 x + 3) d x

Find the following integrals.
$\int \sqrt{x} (3 x^{2} + 2 x + 3) d x .$

2 x^{7} - 128 x

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