We have,
a2−(b−c)2
Since, x2−y2=(x+y)(x−y)
Thus,
⇒[a−(b−c)][a+(b−c)]
⇒(a−b+c)(a+b−c)
Hence, this is the answer.
Factorise a2−81(b−c)2
Factorise:
2(ab+cd)−a2−b2+c2+d2