Factorise ab(x2+1)+x(a2+b2)
ab(x2+1)+x(a2+b2)
Opening the brackets , we have abx2+ab+xa2+xb2 Re-grouping the term , we have abx2+xa2+ab+xb2 bx(ax+b)+a(ax+b) ( Taking the common factors ) (bx+a)(ax+b)
Factorise: ab(x2+1)+x(a2+b2)
Factorise by grouping method:
Factorise :
ab(x2+y2)−xy(a2+b2)