Factorise $x^{3} - 4 x^{2} + 4 x - 16$

$(x^{2} - 4) (x - 4)$

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$(x^{2} + 4) (x - 4)$

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$(x^{2} + 4) (y - 4)$

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$(x^{2} + 16) (x - 4)$

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Solution

The correct option is B
$(x^{2} + 4) (x - 4)$

Given that $x^{3} - 4 x^{2} + 4 x - 16$
$\Rightarrow x^{2} (x - 4) + 4 (x - 4)$ ( Taking $x^{2}$ and 4 as the common factors between the terms)

$\Rightarrow (x^{2} + 4) (x - 4)$

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