Factorise: x4-1
(x2+1) (x +1)(x+1)
(x2+1)(x - 1)(x-1)
(x2+1) (x - 1) (x+1)
(x2-1) (x -1)(x+1)
By using square identity (a + b) (a – b) = a2 – b2 , we get
x4-1 = (x2+1) (x2-1)
= (x2+1)(x-1)(x+1) [Since, (a + b) (a – b) = a2 – b2]
Factorise x2−3x+2 by using the Factor Theorem.
A function: R ⟶ R satisfies the equation f(x) f(y) -f(xy) = x+ y ∀ x, y ∈ R and f(1) > 0, then