For factorizing 6x^2 + 13x + 5);
The first term is, 6x2 its coefficient is 6 .
The middle term is, +13x its coefficient is 13 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 6 • 5 = 30
Step-2 : Find two factors of 30 whose sum equals the coefficient of the middle term, which is 13 .
-30 | + | -1 | = | -31 | ||
-15 | + | -2 | = | -17 | ||
-10 | + | -3 | = | -13 | ||
-6 | + | -5 | = | -11 | ||
-5 | + | -6 | = | -11 | ||
-3 | + | -10 | = | -13 | ||
-2 | + | -15 | = | -17 | ||
-1 | + | -30 | = | -31 | ||
1 | + | 30 | = | 31 | ||
2 | + | 15 | = | 17 | ||
3 | + | 10 | = | 13 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 10
6x2 + 3x + 10x + 5
Step-4 : Add up the first 2 terms, pulling out like factors :
3x • (2x+1)
Add up the last 2 terms, pulling out common factors :
5 • (2x+1)
Step-5 : Add up the four terms of step 4 :
(3x+5) • (2x+1)
Which is the desired factorization